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 True USB Willem Programmer (GQ-2X, GQ-3X, GQ-4X)
 Default DIP Pinouts.
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Eloeri

USA
8 Posts

Posted - 08/17/2020 :  09:06:41  Show Profile  Reply with Quote
From reading various posts on this forum, it seems that each chip has a default DIP pinout dependent on class of chip.

For example:

29F040 uses DIP = 101011100110
27C512 uses DIP = 100010110000

With just the mention of the class of chip in the devices.txt file, for each of the above chips, the DIP pinout is automatic. Some chips, like the AM29F032 have a DIP pinout listed in the devices.txt that overwrites the default pinout, for example:

`Name="AM29F032B*TSOP40",ID="0141",Class="29F040B",Category="FLASH",MFG="AMD",CodeSize="4194304",DIP="100011110101",Adapter="TSOP40B-DIP32(ADP-077 and ADP-082)";`

Even though the class "29F040B" was listed, having the `DIP=` in the line overwrites the default pinout. Where can we find information for each of these default pinouts?
Reply #1

ZLM

2939 Posts

Posted - 08/24/2020 :  16:00:38  Show Profile  Reply with Quote
This DIP address mapping switch data originally came from parallel Willem programmer. For the first 12 bits, it has the same definition of old Parallel Willem programmer DIP switch.

========================================================================
********* For ZIF40 ************
========================================================================

This DIP= is referring to the 12 bits data.
The rest of the 4 bits is in another keyword.


1. Bit 15 : ZIF pin 20 GND control. When it is '1', the pin 16 of ZIF is GND signal. '0' is GND off.
2. Bit 14 : ZIF pin 5 mapped to A19 when it is '1'. When this bit is '1', Bit13 must be '0'
3. Bit 13 : ZIF pin 5 mapped to A18 when it is '1'. When this bit is '1', Bit14 must be '0'
4. Bit 12 : ZIF pin 33 mapped to WE when it is '1'. When this bit is '1', Bit11 must be '0'
5. Bit 11 : ZIF pin 33 mapped to A14 when it is '1'. When this bit is '1', Bit12 must be '0'
6. Bit 10 : ZIF pin 28 mapped to OE when it is '1'. Otherwise the ZIF pin 24 will be logic '0' always.
7. Bit 9 : ZIF pin 32 mapped to A13 when it is '1'. Otherwise the ZIF pin 28 will be logic '0' always.
8. Bit 8 : ZIF pin 26 mapped to CE when it is '1'. Otherwise the ZIF pin 22 will be logic '0' always.
9. Bit 7 : ZIF pin 34 mapped to A13 when it is '1'. Otherwise the ZIF pin 30 will be logic '0' always.
10.Bit 6: ZIF pin 34 mapped to A17 when it is '1'. Otherwise the ZIF pin 30 will be logic '0' always.
11.Bit 5: ZIF pin 35 mapped to WE when it is '1'. When this bit is '1', Bit4 must be '0'
12.Bit 4: ZIF pin 35 mapped to A18 when it is '1'.When this bit is '1', Bit5 must be '0'

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Reply #2

Eloeri

USA
8 Posts

Posted - 09/01/2020 :  19:16:35  Show Profile  Reply with Quote
Thank you for your reply!

I was looking for info on the default state of each chip family, though.

In my example for the AM29F032B, if you didn't include the `DIP=` overwrite, it would default on the class of family DIP settings. But since my example has an overwrite specified, `100011110101`, it would then follow the DIP switch pinout you laid out for bytes 1-12, dependent on the state of each bit. But what is the default DIP settings if the overwrite hadn't been specified?

I hope I'm asking that correctly.
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Reply #3

ZLM

2939 Posts

Posted - 09/13/2020 :  09:52:44  Show Profile  Reply with Quote
Download the RE.6.27

http://www.mcumall.com/download/TrueUSBWillem/USBPrgSetup7.27.exe

Click on the "i" button beside the part name you selected. It included DIP info for the chip.

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